In the adjoining figure, show that ∠A + ∠B +∠C + ∠D + ∠E + �

1.	In the adjoining figure, show that ∠A + ∠B +∠C + ∠D + ∠E + ∠F = 360°.
Answer» We know that the sum of all the angles in triangle ACE is 180^o. ∠A + ∠C + ∠E = 180^o ….. (1) We know that the sum of all the angles in triangle BDF is 180^o. ∠B + ∠D + ∠F = 180^o ….. (2) Now by adding both equations (1) and (2) we get ∠A + ∠C + ∠E + ∠B + ∠D + ∠F = 180^o + 180^o On further calculation ∠A + ∠B + ∠C + ∠D + ∠E + ∠F = 360^o Therefore, it is proved that ∠A + ∠B + ∠C + ∠D + ∠E + ∠F = 360^o.

In the adjoining figure, show that ∠A + ∠B +∠C + ∠D + ∠E + ∠F = 360°.

Answer»

We know that the sum of all the angles in triangle ACE is 180^o.

∠A + ∠C + ∠E = 180^o ….. (1)

We know that the sum of all the angles in triangle BDF is 180^o.

∠B + ∠D + ∠F = 180^o ….. (2)

Now by adding both equations (1) and (2) we get

∠A + ∠C + ∠E + ∠B + ∠D + ∠F = 180^o + 180^o

On further calculation

∠A + ∠B + ∠C + ∠D + ∠E + ∠F = 360^o

Therefore, it is proved that ∠A + ∠B + ∠C + ∠D + ∠E + ∠F = 360^o.