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In the arrangement shown in Fig. 7.100 , mass can be hung from a string with a linear mass density of `2 xx 10^(-3) kg//m` that passes over a light pulley . The string is connected to a vibrator of frequency `700 Hz` and the length of the string between the vibrator and the pulley is `1 m`. If the mass suspended is `16 kg` , then the number of loops formed in the string isA. `1`B. `3`C. `5`D. `8` |
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Answer» Correct Answer - C Number of loops formed `P = 2nL sqrt((mu)/(T)) = 2 xx 700 xx 1 sqrt((2 xx 10^(-3))/(16 xx 9.8))` ` = ( 2xx 700)/( 280) = 5` |
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