InterviewSolution
Saved Bookmarks
| 1. |
In the arrangement shown in Fig. 7.100 , mass can be hung from a string with a linear mass density of `2 xx 10^(-3) kg//m` that passes over a light pulley . The string is connected to a vibrator of frequency `700 Hz` and the length of the string between the vibrator and the pulley is `1 m`. The string is set into vibrations and represented by the equation ` y = 6 sin (( pi x)/( 10)) cm cos (14 xx 10^(3) pi t)` where `x` ane `y` are in `cm` , and `t` in `s`, the maximum displacement at `x = 5 m` from the vibrator isA. `6 cm`B. `3 cm`C. `5 cm`D. `2 cm` |
|
Answer» Correct Answer - A `A(x) = 6 sin ( pi x)/(10)` Maximum displacement at `x = 5 cm` `A(x) = 6 sin ((pi)/(10) xx 5 ) = 6 cm` |
|