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In the arrangement shown in figure coefficient of friction between `5kg` block and incline plane is `mu=0.5`. Friction force acting on the `5kg` block is A. `20 N`B. `15N`C. `10 N`D. `5 N` |
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Answer» Correct Answer - C `f_(min)=mumgcos37^(@)` `20N` But `2g+f=5gsin37^(@)` `rArrf=10N` |
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