1.

In the arrangement shown in figure the ends of an in extensible move downwards with uniform speed u. pulleys A and B are fixed. Find the speed with the mass M moves upwards.

Answer»

Solution :SUPPOSE the distance of point O from the ceiling is y and the distance of point O from each pulley is x and the distance beween the two pulleys is `l`.
`x^(2)=y^(2)+(1^(2))/(4)""(##AKS_DOC_OBJ_PHY_XI_V01_A_C04_SLV_026_S01.png" width="80%">
Diiferentiating the above EQUATION w.r.t. to "t"
`2X((dx)/(dt))=2y((dy)/(dt))+(1)/(4)2l((dl)/(dt))`
But, `u=-(dx)/(dt), v+(dy)/(dt) and (dl)/(dt)`
`:. -xu = yu and v=-u(x)/(y) = usectheta`
`:. VELOCITY of mass = v = usectheta (upwards)


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