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In the arrangement shows in fig. if the surface is smooth then find out acceleration of the block `m_(2)`. |
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Answer» Let accelration of `m_(2)` be a then acceleration of `m_(1)` will be `2a`. for `m_(1):T=m_(1)(2a)` and for `m_(2):m_(2)g-2T=m_(2)a` `rArrm_(2)g-4m_(1)a=m_(2)arArra=(m_(2)g)/(4m_(1)+m_(2))` |
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