In the Bohr's orbit, what is the ratio of total kinetic energy and the total energy of the electron ?

In the Bohr's orbit, what is the ratio of total kinetic energy and the

1.	In the Bohr's orbit, what is the ratio of total kinetic energy and the total energy of the electron ?
Answer» `-1` `-2` `+1` `+2` SOLUTION :`K.E. = (1)/(2) mv^(2), P.E. = - (ZE^(2))/(R)` But electrostatic force = centrifugal force i.e., `(Ze^(2))/(r^(2)) = (mv^(2))/(r) :. P.E. = - mv^(2)` Total energy `= (1)/(2) mv^(2) - mv^(2) = - (1)/(2) mv^(2)` `:.` K.E./Total energy `= -1` Note. Similarly, `E_("total")//P.E. = 1//2` and K.E./P.E. `= - 1//2`