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In the Boolean algebra `bar((bar(A).bar(B))). A` equal toA. `bar(A+B)`B. `A`C. `bar(A.B)`D. `A+B` |
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Answer» Correct Answer - B `bar(bar(A)+bar(B)).A=(bar(bar(A))+bar(bar(B))).A=(A+B).A` `=A.A+AB=A+AB=A(1+B)=A` |
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