In the cell reaction `Cu(S) + 2 Ag^(+) (aq) to Cu^(2+) (aq) + 2 Ag(s) , E_("cell")^(@) = 0.46` V By doubling the concentration of `Cu^(2+) , E_("cell")^(@)` isA. doubledB. halvedC. increases but less than doubleD. decreases by a small fraction .

In the cell reaction `Cu(S) + 2 Ag^(+) (aq) to Cu^(2+) (aq) + 2 Ag(s)

1.	In the cell reaction `Cu(S) + 2 Ag^(+) (aq) to Cu^(2+) (aq) + 2 Ag(s) , E_("cell")^(@) = 0.46` V By doubling the concentration of `Cu^(2+) , E_("cell")^(@)` isA. doubledB. halvedC. increases but less than doubleD. decreases by a small fraction .
Answer» Correct Answer - C `E_("cell") = E_("cell")^(@) - (RT)/(nF) "ln" ([Cu^(2+)])/([Ag^(+)]^(2))` . Doubling `[Cu^(2+)]` decreases the EMF by a small fraction .

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In the cell reaction `Cu(S) + 2 Ag^(+) (aq) to Cu^(2+) (aq) + 2 Ag(s) , E_("cell")^(@) = 0.46` V By doubling the concentration of `Cu^(2+) , E_("cell")^(@)` isA. doubledB. halvedC. increases but less than doubleD. decreases by a small fraction .

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