In the cell represented by `Pb_(s) |Pb^(2+) (1M) ||Ag^(+)(1M) |Ag_(s)` the reducing agents isA. PbB. `Pb^(2+)`C. AgD. `Ag^(+)`

In the cell represented by `Pb_(s) |Pb^(2+) (1M) ||Ag^(+)(1M) |Ag_(s)`

1.	In the cell represented by `Pb_(s) \|Pb^(2+) (1M) \|\|Ag^(+)(1M) \|Ag_(s)` the reducing agents isA. PbB. `Pb^(2+)`C. AgD. `Ag^(+)`
Answer» Correct Answer - A `Pb(s)\| Pb^(2+) (1M) \|\|Ag^(+)(1M)\| Ag_(s)` The compound losing `e^(-)` is called reducing agent. `Pb to Pb^(2+) + 2e^(-)`

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In the cell represented by `Pb_(s) |Pb^(2+) (1M) ||Ag^(+)(1M) |Ag_(s)` the reducing agents isA. PbB. `Pb^(2+)`C. AgD. `Ag^(+)`

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