1.

In the circuit diagram given below five resistances of 10 Ω, 40 Ω, 30 Ω, 20 Ω and 60 Ω are connected as shown to a 12 V battery. Calculate : (a) total resistance in the circuit.(b) total current flowing in the circuit. 

Answer»

Solution :

(i) Equivalent resistance of 10 ohm and 40 ohm resistances (connected in paralel) is R1, given as 

1/R1 = 1/10 + 1/40 = 5/40

R1 = 10 ohm

Equivalent resistance of 30 ohm, 20ohm and 60 ohm resistance (connected in parallel) is R2, given as:

1/R2 = 1/30 + 1/20 + 1/60 = 6/60

R2 = 10ohm

R1 and R2 are connected in series.

Therefore, Total resistance in the circuit is R = R1 +R2 = 8 + 10 = 18 ohm

(ii) Total current flowing in the circuit, I =V/R =12/18 = 0.67 A



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