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In the circuit given below, the current flowing across 5 ohm resistor is 1 amp. Find the current flowing through the other two resistor. |
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Answer» In the given figure, 5Ω, 4Ω and 10Ω resistors are in parallel. In parallel combination, voltage across each resistor is same. It is given that, R = 5Ω I = 1A V = IR = 5V Current across 4Ω resistor I = 5/4 A = 1.25 A Current across 10Ω resistor I = 5/10 = 0.5 A Given, Current flowing through 5 ohms resistor = 1 Ampere R1= 5 ohms, R2= 4 ohms and R3= 10 ohms Now, Potential Difference across 5 ohms resistor will be: V = I × R (By Ohm's Law) V = 1 × 5 V = 5 Volts Let the current flowing through the other two resistors be I2 and I3. Since all the resistors are connected in parallel, the potential difference across the three resistances will be same. Therefore, in R2 : V = I2 × R2 5 = I2 × 4 I2 = 5/4 = 1.25 Amperes Similarly in R3 : V = I3 × R3 5 = I3 × 10 I3 = 5/10 = 0.5 Amperes |
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