1.

In the circuit of adjoining figure the current through `12 Omega` resister will be A. `1 A`B. `(1)/(5) A`C. `(2)/(5) A`D. `0 A`

Answer» Correct Answer - D
(d) Let the current in `12 Omega` resistance is `i`
Applying loop theorem in closed mesh `AEFCA`
`12i = - E + E = 0 :. i= 0`


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