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In the circuit of adjoining figure the current through `12 Omega` resister will be A. `1 A`B. `(1)/(5) A`C. `(2)/(5) A`D. `0 A` |
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Answer» Correct Answer - D (d) Let the current in `12 Omega` resistance is `i` Applying loop theorem in closed mesh `AEFCA` `12i = - E + E = 0 :. i= 0` |
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