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In the circuit shown in Fig. each capacitor has a capacity of `3 muF`. Calculate the quantity fo charge on each capacitor. |
Answer» Total resitance is the circuit ABCD, `R = 4+1 = 5 Omega`. `:.` Current `I = (V)/(R ) = (10)/(5) = 2A` Potential diff. across A and B `= I xx 4 = 2xx4 = 8V` As two capacitors of `3 muF` each are in series, `:.` pot. Diff across each condenser `= (8)/(2) = 4V` charge on each condenser, `q = CV = 3xx4` `= 12 muC` |
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