1.

In the circuit shown in Fig. each capacitor has a capacity of `3 muF`. Calculate the quantity fo charge on each capacitor.

Answer» Total resitance is the circuit ABCD,
`R = 4+1 = 5 Omega`.
`:.` Current `I = (V)/(R ) = (10)/(5) = 2A`
Potential diff. across A and B `= I xx 4 = 2xx4 = 8V`
As two capacitors of `3 muF` each are in series,
`:.` pot. Diff across each condenser `= (8)/(2) = 4V`
charge on each condenser, `q = CV = 3xx4`
`= 12 muC`


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