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    				| 1. | In the circuit shown in Fig, initially `K_(1)` is closed and `K_(2)` is open . What are the charges on each capacitor. Then `K_(1)` was opened and `K_(2)` was closed (order is important). What will be the charge on each capacitor now ? `[C = 1muF]` | 
| Answer» Correct Answer - `"case I:" Q_(1) =18 mu C, Q_(2) = 9mu C"and"Q_(3)=0` `"case I:" Q_(2) =9/2 mu C, Q_(3) = 9/2mu C | |