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In the circuit shown in fig, switch S was closed for long time. At time t-0, teh switch is opened again. The maximum potential difference across teh plates of the capacitor after the switch is opened is A. 10VB. 100VC. 20VD. 200V |
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Answer» Correct Answer - B maximum current `I_(m)=(100)/(50)=2A` Potential drop across the resistro is `2xx50 = 100V` Initial potential difference across capacitor is zero `L_(eq)=(200+50)=250mH` energy stored `=1/2 L_(eff)I_(M)^(2)=1/2 xx250 xx 10^(-3)xx2^(2)=0.5J` when `s_(1)` is opened `1/2 L_(eff)I_(M)^(2)=1/2 CV_(max)^(2)` `V_(max)=sqrt((2xx0.5)/(100 xx 10^(-6)))=100V` . |
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