In the circuit shown in figure a `12 V` battery with unknown internal resistance `r` is connected to another battery with unknown emf E and internal resistance `1Omega ` and to a resistance of `3Omega` carrying a current of `2A`. The current through the rechargeable battery is `1 A` in the direction shown. Figure the unknown current `i` internal resistance r and the emf E.

In the circuit shown in figure a `12 V` battery with unknown internal

1.	In the circuit shown in figure a `12 V` battery with unknown internal resistance `r` is connected to another battery with unknown emf E and internal resistance `1Omega ` and to a resistance of `3Omega` carrying a current of `2A`. The current through the rechargeable battery is `1 A` in the direction shown. Figure the unknown current `i` internal resistance r and the emf E.
Answer» Correct Answer - A::B::C Applying loop law equation in upper loop, we have `E+12-ir-1=0`……….i Applying loop law equation in lower, we have where `i=1+2=3A` `E+t6-1=0`……………ii Solving these two equations we get `E=-5V` and `r=2Omega`

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