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In the circuit shown in figure potential difference between point `A` and `B` is `16 V`. Find the current passing through `2 Omega` resistance. A. `3.5A`B. `3A`C. `4.5A`D. `5.5A` |
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Answer» Correct Answer - A `V_(A)-V_(B)=16` `4i_(1)+2(i_(1)+i_(2))-3+4i_(1)=16` ..(i) `9-i_(2)-2(i_(1)+i_(2))=0` Solving eqs (i) and (ii) `i_(1)=1.5A` and `i_(2)=2A` |
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