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In the circuit shown in figure, the value of R is A. `1Omega`B. `2Omega`C. `3Omega`D. `4Omega` |
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Answer» Correct Answer - B `R_(1)=1Omega, R_(2)=2 Omega, R_(3)=Romega, I_(1)=6 A, I_(2)=2A, R=?` From figure, `I_(3)=11-8=3A` Now in figure` R_(1), R_(2)` and `R_(3)` are in parallel. `:.V=I_(1)R_(1)=I_(3)R_(3)` `:.R_(3)=(I_(1)R_(1))/(I_(3))=(6xx1)/(3)` `R_(3)=R=2Omega` |
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