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In the circuit shown in figure, when the input voltage of the base resistance is 10 V, `V_(be)` is zero and `V_(ce)` is also zero. Then A. 133B. 1330C. 13.3D. 1.33 |
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Answer» Correct Answer - A `I_(B)=(V_(i))/(R_(B))=(10V)/(400xx10^(3)Omega)=25muA` `I_(C)=(10V)/(3kOMega)=3.33mAimplies beta=(I_(C))/(I_(B))=(3.33xx10^(-3))/(25xx10^(-6))=133` |
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