In the circuit shown in the figure, switch S is closed at time `t = 0`. Charge on positive plate of capacitor is `q` at time `t`. (a) Derive a differential equation for q at time t. (b) Solve the equation to write q as a function of time. (c) Put t = 0 and `t = infty` in your equation to get charge on the capacitor at these times.

In the circuit shown in the figure, switch S is closed at time `t = 0`

1.	In the circuit shown in the figure, switch S is closed at time `t = 0`. Charge on positive plate of capacitor is `q` at time `t`. (a) Derive a differential equation for q at time t. (b) Solve the equation to write q as a function of time. (c) Put t = 0 and `t = infty` in your equation to get charge on the capacitor at these times.
Answer» Correct Answer - (a) `14 (dq)/(dt)+(5)/(4)q=12` (b) `q=(48)/(5)[1-e^(-(5t)/(56))]` (c) `0 ; (48)/(5) muC`

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