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In the circuit shown in the figure, the switch S is in position 1 for a long time. Now the switch is thrown to position 2. Find the total heat developed in the circuit till the steady state is reached again. A. 0.04 JB. 0.4 JC. 0.02 JD. 0.2 J |
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Answer» Correct Answer - A a. Initial charge on capacitor : `Q_1 = 2 xx 100 = 200muC` Final charges: `Q_2 = 2 xx 300 = 600 muC` `W_(b)= 300 [Q_2-Q_1] = 12, 0000muJ` `DeltaU = 1/2 C [300^2 - 100^2] = 80000 muJ` Heat `= W_(b) - DeltaU = 40000 muJ = 0.04J` |
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