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| 1. |
In the circuit shown, r = 4 Omega, C = 2mu F (a) Find the current coming out of the battery just after the switch is closed(b) Find charge on each capacitor in the steady state condition |
| Answer» <html><body><p></p>Solution :(a) Due to symmetry. the points of equal potential are joined together, and the circuit may be reducedas<br/>`R_(13)=(r)/(2)+(r)/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)+(r)/(4)+(r)/(2)=(3)/(2)r`<br/>`Here,r=4Omega,R_(13)=(3)/(2)(4)=6omega`<br/><a href="https://interviewquestions.tuteehub.com/tag/thus-2307358" style="font-weight:bold;" target="_blank" title="Click to know more about THUS">THUS</a>,`I=(24)/(R_(13)=(24)/(6)=4A`<br/>(b) in the steady-state condition, the circuit may be reduced as,` R_(13) = 2r = 2(4)Omega = 8Omega`<br/>`I=(24)/(8)=<a href="https://interviewquestions.tuteehub.com/tag/3a-310574" style="font-weight:bold;" target="_blank" title="Click to know more about 3A">3A</a>``V_(56)=(2r)(1)/(2)=Ir=(3)(4)=12V`<br/>Equivalent capacitance between 5 and 6 is<br/>`C_(56)=(<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>)/(2)=1muF`<br/>`thereforeq1_(56)=C_(56)V_(56)=12muC`<br/>NOW,`V_(97)=V_(17)-V_(<a href="https://interviewquestions.tuteehub.com/tag/19-280618" style="font-weight:bold;" target="_blank" title="Click to know more about 19">19</a>)`<br/>`=-r(1)/(2)+2(rl)/(2)=(rl)/(2)=((4)(3))/(2)=6V`<br/>therefore`q_(97)=(2)(6)=12muC`<br/> Similarly, `q_(89) = 12muC`<br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FIITJEE_PHY_MB_07_C03_SLV_020_S01.png" width="80%"/> <br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FIITJEE_PHY_MB_07_C03_SLV_020_S02.png" width="80%"/></body></html> | |