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In the curcuit shown in figure `R_1=R_2=R_3=10Omega`. Find the currents through `R_1` and `R_2` |
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Answer» Correct Answer - A `V_(R_1)=0` `:. i_(R_1)=0` `V_(R_2)=V_(R_3)=10V` `:. I_(R_2)=i_(R_3)=10/10=1A` |
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