InterviewSolution
Saved Bookmarks
| 1. |
In the determination of the internal resistance of a cell using a potentiometer, when the cell is shunted by a resistance R and connected in the secondary circuit, the balance length is found to be `L_(1)`. On doubling the shunt resistance, the balance length is found to increase to `L_(2)`. The value of the internal resistance isA. `(2R(L_(2)L_(1)))/((L_(1)-2L_(2)))`B. `(2R(L_(2)-L_(1)))/((2L_(1)-L_(2)))`C. `(R(L_(2)-L_(1)))/((L_(1)-2L_(2)))`D. `(R(L_(2)-L_(1)))/((2L_(1)-L_(2)))` |
|
Answer» Correct Answer - B `((E)/(R+r))R=K.l` |
|