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In the diagram ABCD is a rectangle with AE = EF = FB, the ratio of the areas of triangle CEF and that of rectangle ABCD is (1) 1 : 6 (2) 1 : 8 (3) 1 : 9 (4) 1 : 10 |
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Answer» (1) 1 : 6 ∴ Ar(CEF) = \(\frac{1}{3}\) Ar (ABC) = \(\frac{1}{6}\) Ar (ABCD) ∴ \(\frac{Ar(CEF)}{Ar(ABCD)}=\frac{1}{6}\) |
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