In the diagram shown in figure, match the following columns (take g=10 ms^(-2)) {:("Column I","Column II"),("(A) Normal reaction","(p) 12 SI unit"),("(B) Force of friction","(q) 20 SI unit"),("(C) Acceleration of block","(r) zero"),(,"(s) 2 SI unit"):}

In the diagram shown in figure, match the following columns (take g=10

1.	In the diagram shown in figure, match the following columns (take g=10 ms^(-2)) {:("Column I","Column II"),("(A) Normal reaction","(p) 12 SI unit"),("(B) Force of friction","(q) 20 SI unit"),("(C) Acceleration of block","(r) zero"),(,"(s) 2 SI unit"):}
Answer» Solution :`N=mg-20sqrt(2) SIN 45^(@) =20N` `F mu_(k)N=12N` Since, `20sqrt(2) cos 45^(@) gt muN` block will MOVE and kinetic friction will act, `a=(20sqrt(2) cos 45^(@)-mu_(k)N)/(m)=(20-12)/(4)=2 MS^(-2)`