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In the diagram shown, the block A and B are of the same mass M and the mass of the block C is `(M_(1))`. Friction is present only under the block A. the whole system is suddenly released from the state of rest. The minimum coefficient of friction on keep the block A in the state of rest is equal to . A. (a) `(M_(1))/(M)`B. (b) `(2M_(1))/(M)`C. (c) `(M_(1))/(2M)`D. (d) None of these` |
Answer» Correct Answer - B `Let X_(m)` is maximum elongation of spring. Then, incerase in potential energy of spring`=`decrease in potential energy of `C`. `:. 1/2KX_(m)^(2) =M_(1)gX_(m)` or `KX_(m) =`maximum spring force `=2M_(1)g -mu_("min") Mg` `:. mu_("min") =(2M_(1))/(M)` |
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