In the direction , N_(2) + 3 H_(2) hArr 2 NH_(3)at equilibrium , helium gas is injected into the vessel without disturbing the overallpressure of the system. What will be the effect on the equilibrium ?

In the direction , N_(2) + 3 H_(2) hArr 2 NH_(3)at equilibrium , heliu

1.	In the direction , N_(2) + 3 H_(2) hArr 2 NH_(3)at equilibrium , helium gas is injected into the vessel without disturbing the overallpressure of the system. What will be the effect on the equilibrium ?
Answer» Solution :` K_(C) =[NH_(3)]^(2) /([N_(2) ] [ H_(2)]^(3)) ` As PRESSURE is kept constant, volume will increase. HENCE molar concentration of `NH_(3), N_(2) and H_(2)` will DECREASE. As there are two concentrations terms in numerator and four concentration terms in the DENOMINATOR , to keep `K_(c)` constant, decrease in`NH_(3)` should be more i.e, equilibrium will shift in teh backward direction.