In the disproportionation reaction 3 HCIO_(3) rarr HCIO_(4) +CI_(2) + 2 O_(2) +H_(2)O What is the equivalent weight of the oxidising agent ? (Give molecular mass of HCIO_(3) =84.45 u)

In the disproportionation reaction 3 HCIO_(3) rarr HCIO_(4) +CI_(2) +

1.	In the disproportionation reaction 3 HCIO_(3) rarr HCIO_(4) +CI_(2) + 2 O_(2) +H_(2)O What is the equivalent weight of the oxidising agent ? (Give molecular mass of HCIO_(3) =84.45 u)
Answer» Solution :`3 HCIO_(3) rarr HCIO_(4)+CI_(2)+2O_(2)+H_(2)O` SINCE O.N of CI decreases from +5 inch `HCIO_(3)` to O in `CI_(2)` therefore `HCIO_(3)` acts as the oxidising agent in other words O.N DECREASE by 5 5 and the equivalent mass of the oxidising agent `(HCIO_(3))` i.e `=Mol mass //5 =84.45//5 =16.89`