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In the disproportionation reaction, `3HCIO_(3) rarr HCIO_(4) +CI_(2)+2O_(2)+H_(2)O` What is the equivalent mass of the oxidising agnet ? |
Answer» `overset(x)CIO_(3)rarr overset(0)CI2, x+2(-3)=-1or x=-1+6=5` change in oxidation number= +5 Equivalent mass of `CIO_(3) (Molecular mass)/(Oxidation number change")`=`(35..5+48)/(5)` `= (83.56)/(5)=16.7` |
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