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In the double displacement reaction between aqueous potassium iodide and aqueous lead nitrate, a yellow precipitate is formed is of : 1. KNO3 2. PbNO3 3. Pbl2 4. KI |
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Answer» Answer: PbNO3 Explanation: Correct option is B LEAD acetate 2KI(aq)+Pb(NO 3
) 2
(aq)→PbI 2
(s)+2KNO 3
In the above DOUBLE displacement reaction, potassium IODIDE(KI) and lead nitrate (Pb(NO 3)2 dissociate in their aqueous states to form ions. The lead (Pb 2+) ions combine with the iodide (I) ions to form PRECIPITATES of lead iodide (PPbI2) |
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