InterviewSolution
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InterviewSolution
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In the double-slit experiment, the electric fields of the waves arriving at point P are given by E_(1)=(2.00 mu V // m)sin[(1.26 xx 10^(15))t] E_(2)=(2.00 mu V // m)sin[(1.26=10^(15))t+38.6 "rad"] where timer is in seconds. (a) What is the amplitude of the resultant electric field at point P? (b) What is the ratio of the intensity I_(P) at point P to the intensity I_("cen") at the center of the interference pattern? (C) Describe where point P is in the interference pattern by giving the maximum or minimum on which it lies, or the maximum and minimum between which it lies. In a phasor diagram of the electric fields, (d) at what rate would the phasors rotate around the origin and (e) what is the angle between the phasors? |
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Answer» <P> Solution :(a) 2.33 `mu V // m`, (b) 0.338, (c) POINT P is between the sixth side MAXIMUM (at which `PHI= 6` wavelengths) and the seventh minimum (at which `phi= 6(1)/(2)` wavelengths), (d) `1.26 xx 10^(15) rad // s`, (e) `2270^(@)` |
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