In the electrochemical reaction 2Fe^(3+)+Zn to Zn^(2+) + 2Fe^(2+) Increasing the concentration of Fe^(2+)

In the electrochemical reaction 2Fe^(3+)+Zn to Zn^(2+) + 2Fe^(2+) In

1.	In the electrochemical reaction 2Fe^(3+)+Zn to Zn^(2+) + 2Fe^(2+) Increasing the concentration of Fe^(2+)
Answer» increases cell emf increases the current flow decreases the cell emf alters the PH of the solution. Solution :NERNST EQUATION , `E_("cell")=E_("cell")^(@)-(2.303RT)/(2F)"log"([ZN^(2+)][Fe^(2+)]^(2))/([Fe^(3+)]^(2))` Increasing `[Fe^(2+)]` will decrease the `E_("cell")`.