In the equation 2x2 – hx + 2k = 0, the sum of the roots is 4 and the

1.	In the equation 2x2 – hx + 2k = 0, the sum of the roots is 4 and the product of the roots is -3. Then h and k have the values ………………… respectively. A) 8 and -3 B) 8 and 6 C) 4 and -3 D) -3 and 8
Answer» Correct option is (A) 8 and -3 Given equation is \(2x^2-hx + 2k = 0\) \(\therefore\) Sum of roots \(=\frac{-(-h)}2=\frac{h}2\) \(\Rightarrow\frac h2=4\) \((\because\) Sum of roots = 4 (given)) \(\Rightarrow\) h = 8 And product of roots \(=\frac{2k}2=k\) \(\Rightarrow\) k = -3 \((\because\) Product of roots = -3 (given)) Hence, h = 8 & k = -3 Correct option is A) 8 and -3

In the equation 2x2 – hx + 2k = 0, the sum of the roots is 4 and the product of the roots is -3. Then h and k have the values ………………… respectively. A) 8 and -3 B) 8 and 6 C) 4 and -3 D) -3 and 8

Answer»

Correct option is (A) 8 and -3

Given equation is

\(2x^2-hx + 2k = 0\)

\(\therefore\) Sum of roots \(=\frac{-(-h)}2=\frac{h}2\)

\(\Rightarrow\frac h2=4\) \((\because\) Sum of roots = 4 (given))

\(\Rightarrow\) h = 8

And product of roots \(=\frac{2k}2=k\)

\(\Rightarrow\) k = -3 \((\because\) Product of roots = -3 (given))

Hence, h = 8 & k = -3

Correct option is A) 8 and -3