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In the equation `A+B+C+D+E=FG`. Where `FG` is the two digit number whose value is `10F+G` and letters `A,B,C,D,E,F` and `G` each represents different and `FG` is as large as possible A five digit number is made using digits `A,B,C,D,E,F,G` (repetition not allowed), then which of the following is incorrectA. probability that number made is divisible by 5 is `1/7`B. probability that number made is divisible by is `2/7`C. probability that number made is divisible by 4 is `2/7`D. probability that number made is divisible by 4 is `1/7` |
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Answer» Correct Answer - D `9+8+6+5+4=32` Set `P(A,B,C,D,E,F,G)=(2,3,4,5,6,8,9)` `n(S)=.^(7)C_(5)xx5!` Total numbers divisible by `5=.^(6)C_(4)xx4!` Total numbers divisible by `3=.^(3)C_(1)xx5!+.^(3)C_(2)xx5!=6!` Total number divisible by `4=720` |
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