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In the equation `H_(2)S+2HNO_(3) rarr 2H_(2)O+2NO_(2)+S` The equivalent weight of hydrogen sulphide isA. `17`B. `68`C. `34`D. `16` |
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Answer» Correct Answer - A `H_(2)S rarr overset(0)(S)+2e` Equivalent wt. `=(Mol wt.)/(2)=(34)/(2)=17` |
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