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In the equation y= a sin `(omega t+ kx)` t and x stand for time and distance respectively. What are the dimensions of `omega//k`? |
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Answer» Correct Answer - `LT^(-1)` The given equation is `y =a sin (omega t - kx)` As angle is dimensionless, therefore, `(omegat- kx)` = angle `omega =(1)/(t) = T^(-1) and k = (1)/(k) = L^(-1)` `(omega)/(k) = (T^(-1))/(L^(-1)) = [LT^(-1]` |
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