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In the equilibrium, 2A(g)hArr2B(g)+C_(2)(g) the equilibrium concentrations of A, B and C_(2) at 400 K are 1xx10^(-4)M,2.0xx10^(-3)M, 1.5xx10^(-4)M respectively. The value of K_(C) for the equilibrium at 400 K is |
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Answer» Solution :`2A(g)hArr 2B(g)+C_(2)(g)`, equilibrium concentrations `[A] = 1xx10^(-4)M` `[B] = 2.0xx10^(-3)M` `[C_(2)]=1.5xx10^(-4)M` `K_(C )=([B]^(2)[C_(2)])/([A]^(2))` `K_(C )=([2.0xx10^(-3)]^(2)[1.5xx10^(-4)])/([1xx10^(-4)]^(2))` `K_(C )=6XX10^(-2)` |
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