InterviewSolution
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InterviewSolution
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In the equilibrium, ` CaCO_(3) (s) hArr CaO (s) + CO_(2) (g) , " at 1073 K,the pressure of " CO_(2) " is found to be " 2*5 xx 10^(4) Pa.` What is the equilibrium constant of this reaaction at 1073 K ? |
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Answer» With reference to the standard state pressure of 1 bar, 1.e., `10^(5)` Pa, ` K_(p) = p_(cO_(2)) = (2*5 xx 10^(4) Pa)/(P^(0)) = ( 2.5 xx 10^(4) pa)/(10^(5) Pa) = 0.25` |
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