In the equilibrium CO(g) + 3H_(2(g)) hArr CH_(4(g)) + H_2O_((g))if the volume made half than what is the effect on K ? Why ?

In the equilibrium CO(g) + 3H_(2(g)) hArr CH_(4(g)) + H_2O_((g))if the

1.	In the equilibrium CO(g) + 3H_(2(g)) hArr CH_(4(g)) + H_2O_((g))if the volume made half than what is the effect on K ? Why ?
Answer» Solution :At constant temperature K is constant. So there is no EFFECT on K. As the volume decreases pressure INCREASES. So reaction MOVES in forward direction TILL `Q_c = K`. and again equilibrium ESTABLISHED. but K remain constant.