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In the estimation of sulphur by Carius method, 0.468g of an organic sulphur compound afforded 0.668g of barium sulphate. Find out the percentage of sulphur in the given compound. (Ba= 137, S=32, O=16) |
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Answer» Solution :molar mass of `BaSO_(4)= 137 + 32 (16 xx 4)= 233g` `UNDERSET(32g)(S) rarr underset(233g)(BaSO_(4))` contain 32g sulphur, `:. 0.668g BaSO_(4)` contain Sulphur `= (32 xx 0.668)/(233) gm` % `S = (32)/(233) xx (0.668)/(0.468) xx 100` = 19.60% |
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