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In the estimation of sulphur by carius method, 0.468 gm of an organic sulphur compound afforded 0.668 gm of barium sulphate. Find out the percentage of sulphur in the given compound. |
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Answer» Total mass of organic compound = 0.468 g [Given] Mass of barium sulphate formed = 0.668 g [Given] 1 mol of `BaSO_(4)` = 233 g of `BaSO_(4)` = 32 g of sulphur Thus, 0.668 g of `BaSO_(4)` contains `(32xx0.668)/233g` of sulphur = 0.0917 g of sulphur Therefore, percentage of sulphur = `0.0197/0.468xx100=19.59%` Hence, the percentage of sulphur in the given compound is 19.59 %. |
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