In the expansion of (x+y)25, 1st term from the end = (26−p)th term from the beginning 2nd term from the end = (26−q)th term from the beginning 3rd term from the end = (26−r)th term from the beginning 10st term from the end = (26−s)th term from the beginning Find the value of p+q+r+s __

In the expansion of (x+y)25, 1st term from the end = (26−p)th term f

1.	In the expansion of (x+y)25, 1st term from the end = (26−p)th term from the beginning 2nd term from the end = (26−q)th term from the beginning 3rd term from the end = (26−r)th term from the beginning 10st term from the end = (26−s)th term from the beginning Find the value of p+q+r+s __
Answer» In the expansion of $(x + y)^{25}$ , $1^{s t}$ term from the end = $(26 - p)^{t h}$ term from the beginning $2^{n d}$ term from the end = $(26 - q)^{t h}$ term from the beginning $3^{r d}$ term from the end = $(26 - r)^{t h}$ term from the beginning $10^{s t}$ term from the end = $(26 - s)^{t h}$ term from the beginning Find the value of p+q+r+s __