In the fermentation of sugar, the concentration is reduced from 0.12M

1.	In the fermentation of sugar, the concentration is reduced from 0.12M to 0.06M in 10h and to 0.03M in 20h. The order of the reaction is?
Answer» Answer: EXPLANATION: Given, CONCENTRATION is reduced from 0.12 M to 0.06 M in 10 h. So, t 1/2 =10h Conc reduced from 0.12 M to 0.03 M in 20hr. So, t 3/4 =20h t 3/4 =2×t 1/2 This is valid only for 1st ORDER Reaction. So,Order is 1 pls mark me brainlest

In the fermentation of sugar, the concentration is reduced from 0.12M to 0.06M in 10h and to 0.03M in 20h. The order of the reaction is?

Answer»

Answer:

EXPLANATION:

Given, CONCENTRATION is reduced from 0.12 M to 0.06 M in 10 h.

So, t

1/2

=10h

Conc reduced from 0.12 M to 0.03 M in 20hr.

So, t

3/4

=20h

3/4

=2×t

1/2

This is valid only for 1st ORDER Reaction.

So,Order is 1

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