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In the fig. shown the circuit is in steady state. How long does it take for the capacitor to discharge until the potential difference across it becomes `1 V` ?A. `1766.1 mu s`B. `333.34 mu s`C. `1000 mu s`D. `333.34 s` |
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Answer» Correct Answer - C `q=q_(0) e^(-t//tau) V=V_(0) e^(-t//tau) i=20 e^((-3t)/(1000))t=1000s`. |
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