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In the fig. shown the circuit is in steady state. If the battery is disconnected give the capacitor charge as a function of time.A. `Q=200 e^(-3t//10)`B. `Q=200e^(-3t//1000)`C. `Q=200 e^(-3t)`D. `Q = 100 e^(-3000 t)` |
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Answer» Correct Answer - B `q =q_(0) e^(-t//r) q_() = 200 muc tau = RC` `R` is effective resistance across capacitor. |
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