In the figure a truck is moving on a horizontal surface with acceleration a. Two blocks of equal masses m are supported on the truck as shown in figure. Given that when the block at the top surface is just about to slide, other block remains hanging at 30^(@) from the vertical. In this system.

In the figure a truck is moving on a horizontal surface with accelerat

1.	In the figure a truck is moving on a horizontal surface with acceleration a. Two blocks of equal masses m are supported on the truck as shown in figure. Given that when the block at the top surface is just about to slide, other block remains hanging at 30^(@) from the vertical. In this system.
Answer» `a=(g)/(sqrt(3))` `T=(2)/(sqrt(3))MG` `MU=(5-sqrt(3))/(3sqrt(3))` `T=(sqrt(3))/(2)mg` Solution :`T sin 30^(@)=ma …..(1)` `T cos 30^(@)=mg …….(2)` dividing equation `(1)` by equation `(2)` `tan 30^(@)=(a)/(g)` `rArr a=gtan 30^(@)` `rArr a=(g)/(sqrt(3))` Ans. From `(2)T=(mg)/(cos 30^(@))=(2MG)/(sqrt(3))`Ans. and `mu mg-T=ma` `rArr mu mg=T+ma=(2mg)/(sqrt(3))+ma` `=(2mg)/(sqrt(3))+(mg)/(sqrt(3))` `rArr mumg=(3MG)/(sqrt(3))=sqrt(3)mg` `=mu=sqrt(3) Ans.`