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In the figure AB is the diameter of the circle. CD = 10 cm. BC is 15 cm less than Ac. Find AB? |
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Answer» AC x CB = CD2 AC = x x(x-15) = 102 x2 - 15x = 100 \(x^2-15x+\frac{225}{4}=100+\frac{225}{4}\) \((x-\frac{15}{2})^2=\frac{625}{4},x-\frac{15}{2}=\frac{25}{2}\) \(x=\frac{25}{2}+\frac{15}{2},\) ∴ AB = 20 + 5 = 25 cm |
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