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In the figure , ABCD is a parallelogram in which ∠A=60∘. If the bisectors of ∠A and ∠B meet at P, prove that AD =DP, PC =BC and DC = 2AD. |
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Answer» In the figure , ABCD is a parallelogram in which ∠A=60∘. If the bisectors of ∠A and ∠B meet at P, prove that AD =DP, PC =BC and DC = 2AD.
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